CareerCup

Given a random function with equal probability of getting 1 or 0 ie 50% each. write a custom function which uses the above random function such that your function should return 1 with 75% probability and 0 with 25% probability

You are given a matrix with N rows and N columns. Elements in matrix can be either 1 or 0. Each row and column of matrix is sorted in ascending order.
Find number of 0-s in the given matrix.
Example:

0 0 1
0 1 1
1 1 1
Answer: 3

0 0
0 0
Answer: 4

Update: Expected complexity is O(log(N)). The best I've seen in comments is still O(N).

Update2: Alright, guys, sorry for a bit of trolling. Obviously this is not possible to do faster than O(N). Here is why: take a diagonal (N, 1), (N-1, 2), ... (1, N). Suppose input matrix has all 0's above this diagonal and all 1's under this diagonal. So only diagonal elements vary. Clearly, diagonal elements do not depend on each other. So we have to analyze each diagonal element which is O(N).
Nice job, @gen-y-s :)

Given M nodes and at most one outgoing edge from any node. Given Q operations where an operation is either
i) 1 Z where Z represent the source node, print the terminal node if a coin travels through edges. In case, if node Z lies in a cycle, print LOOP. 1 is the operation type
ii) 2 Z where Z represents node for which the outgoing edge is removed and 2 is operation type.
Operations are performed in order in which they are given.
M <= 3*10^5, Q <= 3*10^5

Input
First line contains integer M.
Second line contains M integers, where ith integer represents outgoing edge from ith node. If outgoing edge is 0, that means there is no outgoing edge from this node.
Third line contains integer Q followed by Q lines where each line is either 1 Z, or 2 Z where Z is node number. Nodes are 1-indexed.

This question was asked in coding test. Can somebody please help me with this problem with the given constraints?

Write a class to take in a large arbitrary number, also provide a function to increment the number. The number will be passed on as an array of integers.

given an arraylist of say 50 lac entries and an empty queue, Design a multi-threading bases system which can copy the items in arraylist in a queue parallely
How many threads can be spawned based on what criterion ? Basically the interviewer wanted to know how to implement an algorithm where we can design number of threads to be spawned ?

Let "t" be a good number if "t" can be written as sum of 2 cubes in at least 2 distinct ways. Given n, write a method which prints all good numbers up to and including n.

Write a program that takes an integer and prints out all ways to multiply smaller integers that equal the original number, without repeating sets of factors. In other words, if your output contains 4 * 3, you should not print out 3 * 4 again as that would be a repeating set. Note that this is not asking for prime factorization only. Also, you can assume that the input integers are reasonable in size; correctness is more important than efficiency.

Eg: PrintFactors(12) 12 * 1 6 * 2 4 * 3 3 * 2 * 2

A robot on a plane has 2 types of commands:
1. move forward by X units (X is integer 0 <= X <= 10000 )
2. rotate by X degrees (X is integer in range [-180, 180] )
A robot looks like

def robot(commands):
    while True:
        for command in commands:
            execute(command)

Given a list of commands (of size <= 10000) tell if it's possible to build a wall around the robot such that he will never touch it.

Example:

[move(10), rotate(180), move(10)] -> answer is yes
[move(10), rotate(45), move(10), rotate(-45), move(10), rotate(45)] - answer is no

You are given a range [first, last], initially white. You need to paint it black.
For this purpose you have a set of triples
[(f, l, cost), ...] - where each triple means that you can paint range [f, l] for `cost` coins (limitations: cost is floating point >= 0, f, l, first, last are integers).
Find minimum cost needed to paint the whole range [first, last] or return -1 if it's impossible
Example:

[first, last] = [0, 5] and set of triples is
[[0, 5, 10], [0, 4, 1], [0, 2,5], [2, 5, 1]]

Clearly the answer is to take [0, 4, 1] and [2, 5, 1] - the total cost will be 2.
Another example:

[first, last] = [0, 5]
triples are [[1,4, 10], [2, 5, 6]]

answer is -1, because it's impossible to color whole range.

Given an array of length N and an integer K, sort the array as much as possible such that no element travels more than k positions to its left - an element however can travel as much as it likes to its right.

given 2 strings A and B. generate all possible solutions when B is merged in A.
Ex: A = "hey"
B: "sam"
then solutions are :

heysam,hseaym,hesaym,sahemy etc.

notice that order should be the same for both of strings while merging.

/*
Prison cell question
In a kingdom there are prison cells (numbered 1 to P) built to form a straight line segment. Cells number i and i+1 are adjacent, and prisoners in adjacent cells are called "neighbors." A wall with a window separates adjacent cells, and neighbors can communicate through that window.
All prisoners live in peace until a prisoner is released. When that happens, the released prisoner's neighbors find out, and each communicates this to his other neighbor. That prisoner passes it on to his other neighbor, and so on until they reach a prisoner with no other neighbor (because he is in cell 1, or in cell P, or the other adjacent cell is empty). A prisoner who discovers that another prisoner has been released will angrily break everything in his cell, unless he is bribed with a gold coin. So, after releasing a prisoner in cell A, all prisoners housed on either side of cell A - until cell 1, cell P or an empty cell - need to be bribed.
Assume that each prison cell is initially occupied by exactly one prisoner, and that only one prisoner can be released per day. Given the list of Q prisoners to be released in Q days, find the minimum total number of gold coins needed as bribes if the prisoners may be released in any order.
Note that each bribe only has an effect for one day. If a prisoner who was bribed yesterday hears about another released prisoner today, then he needs to be bribed again.

Task: find the minimum amount of gold we need to bribe the prisoners so that the chosen prisoners can be released without causing cell destruction.
Input example:
8 cells, 1 prisoner has to be released. The prisoner to be released is the 3rd one.
|1|2|3|4|5|6|7|8|
7 gold coins
another example:
20 cells, 3 prisoners to be released: 3, 6 and 14
|1|2| |4|5| |7|8|9|10|11|12|13| |15|16|17|18|19|20|
release prisoner 3: 19 gold coins
release prisoner 6: 16 gold coins
release prisoner 14: 13 gold coins

release 14: 19 gold coins
release 6: 12 gold coins
release 3: 4 gold coins

input:
number of cells
prisoners that need to be released
output:
least number of gold coins we need to give
*/

Write a method to count the number of 2s between 0 and n.*

Design an algorithm to figure out if someone has won in a game of tic-tac-toe.

Design a hashMap in Java. Implement put, get, remove, resize methods.

1) Narrate an instance you optimized or improved a software design.
2) Given a chance how would you re-think some of the design aspects?

Design a Twitter feeds API. How would you actually connect it from a mobile? What happens behind the Twitter network? how do the Trends get published? From where does Twitter get the information for a particular trend(Eg: #Obama, #nfl) and publish it out? What protocol does it use? How do you connect to Twitter API? How does Twitter handle multiple connections?

1) Describe your most proudest project, least proudest project
2) Most inpiring teammate, what did he do?
3) Most awesome manager? Why was he so good?

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

Write a function that takes a string representing as value in roman numbers and returns it as an integer.

Implement the following

   /**
     * 
     *    romanNumber("III") = 3
     *    romanNumber("IV") = 4
     */
   int romanNumber(String roman) {
      // ...
   }

Write a function that takes a number and returns the square root

Implement the following

   double sqrt(double d) {
      // ...
   }

Given a stream of characters (e.g. acacabcatghhellomvnsdb) and a list of words (e.g. ["aca","cat","hello","world"] ) find and display count of each and every word once the stream ends.(Like : "aca" : 2 , "cat" : 1 , "hello" : 1 , "world" : 0 ).

You are given a graph, some edges are black, some are red. Find a spanning tree with one restriction: if we take some node as root, every path from it to some leaf node must consist of alternating red-black-red-black edges. That is, no path from root to leaf must contain sequential black-black edges or red-red edges.
You are guaranteed that such spanning tree exists.

Provide a function that allow to compare two strings lexicography, having in mind that these words may contain digraphs (two letters together represents a single one i.e in Spanish ch is a single character ).
This in order to be able to sort a list of words.

There are N coins with coordinates (x, y) where x >0 and y >0
You start at (0, 0) and you can only do steps of form (dx, dy) where dx >0 and dy > 0
Print the maximum number of coins that you can collect.

Clarification: you can do as many moves as you wish, the point is to collect maximum number of coins. If you are located at position (a, b) you may jump to position (a+dx, b+dy) for all dx > 0 and dy > 0

@krbchd: Your algorithm may output incorrect values. Suppose there are points (5, 7), (5, 8), (5, 9) for y coordinates LIS will output 7, 8, 9, however since these points are on the same x axis, you can choose only one of them.

Find all the customers who spent >2 minutes on Page "XYZ" & purchased
>2 items of cofffee_X && gave a review of >3
Objects given:

class PageView {
private String URL;
private String customerID;
private Integer timeSpent;}

class Purchase {

private String productID;
private String customerID;
private Integer itemsPurchased;}

class Review {
private String productID;
private String customerID;
private Integer reviewPoints;}

#define mysizeof(x) (char*)(&x+1)-(char*)(&x)

//why casting is done to char* for mysizeof
// casting it to void also works

Given a packed file with 1Tb of 64-bit doubles (first 8 bytes are first double, next 8 bytes are next, etc) find the exact value of median. For simplicity assume the number of doubles is odd.
You can't modify the file and you have only 8Gb of free memory.

Update: you may use no more than two passes through file and your algorithm shouldn't rely on some nature of file - it should work in all cases.

Given an array of numbers, find the longest alternating subsequence. That is, a subsequence [a1, a2, a3, ..., ak] where a1 > a2, a3 < a2, a4 > a3, ... or vice versa (Graphically looks like /\/\/\... or \/\/\/\....

Jack love playing games, Gluttonous snake( an old game in Nokia era) is one of his favorite. However, after playing gluttonous snake so many times, he finally got bored with the game, so he changed the rules:

Rule 1: Write a code to find the Max sum path in a grid (2-D array), with dimension with n rows and m column (1<=n,m<=500)

Rule 2: In the 2D Array, each cell (elements) contains a value v in the array is from (-1<=v<=99999)

Rule 3. You can start from any position of the leftest column (border) of the array to the rightest(border) column of the array to calculate the Max Sum path.

Rule 4. You can move up, right, down, and CAN'T move left, and can visit each element only one time.

Rule 5.If the element is -1, it means the path is blocked, and you can't go through the path (calculate it in the sum), you have to choose other path to calculate the sum.

For example, if a 4*4 array grid
{{-1,3,2,1}
{2,-1,2,4}
{2,2,-1,3}
{4,2,1,2}};
The max sum path is : (from grid[4][0])
4-->up-->2-->left-->2-->down-->2-->left-->
1-->left-->2-->up-->3-->up-->4-->up-->1

and the sum is 4+2+2+2+1+2+3+4+1 =21

Thank you

Here is my code, I am new in Java and there is still lots of improvements
import java.util.*;
public class MainClass {

public static void main(String[] args) {

@SuppressWarnings("resource")
Scanner rowDimension = new Scanner(System.in);
System.out.print("Enter the number of rows: ");
int firstInput = rowDimension.nextInt();

@SuppressWarnings("resource")
Scanner columnDimension = new Scanner(System.in);
System.out.print("Enter the number of columns: ");
int secondInput = columnDimension.nextInt();

//Input two number to generate 2D Array
Integer [][] array = new Integer[firstInput][secondInput];
//The purpose of the array is check the wall (cell value = -1)
boolean [][] visited = new boolean[firstInput][secondInput];

//Use Math.random() to generate the cell of the array
int[][] randomTable = new int[firstInput][secondInput];
for (int row = 0; row < firstInput; row++) {
for (int column = 0; column < secondInput; column++) {
// multiply by 1000000 to get a number between 0 and 99999
randomTable[row][column] = (int)(Math.random() * 1000000 -1);
System.out.print(randomTable[row][column] + " ");
}
System.out.println();
}

//Start form the left-down location of grid
int i = firstInput-1, j = 0;
visited[i][j] = true;
double sum = array[i][j];
while(true)
{
int max = -1;
int maxi = 0, maxj = 0;

//Case1 : choose path: UP
if(i-1 >= 0 && i-1<= firstInput-1 && j>=0 && j<= secondInput-1 && array[i-1][j] != null && array[i-1][j]>max && !visited[i-1][j])
{
max = array[i-1][j];
maxi = i-1;
maxj = j;
}

//Case2 : choose path: Down
if(i+1 >= 0 && i+1<= firstInput-1 && j>=0 && j<= secondInput-1 &&array[i+1][j] != null && array[i+1][j]>max && !visited[i+1][j])
{
max = array[i+1][j];
maxi = i+1;
maxj = j;
}

//Case3 : choose path: Right
if(i >= 0 && i<= firstInput-1 && j+1>=0 && j+1<= secondInput-1 && array[i][j+1] != null && array[i][j+1]>max && !visited[i][j+1])
{
max = array[i][j+1];
maxi = i;
maxj = j+1;
}

i = maxi;
j = maxj;
visited[i][j] = true;
sum += max;

//To the destination : Right-Up location of the grid
if(i == 0 && j == secondInput-1)
break;
}
System.out.println(sum);

}
}