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The probable catch in the logic is when there is overflow upon addition.
- Ajith April 03, 2012The best logic for this flow of finding an average of 'n' numbers is:
double avg=0;
for(i:1 to n)
avg += (double)Arr[i] / (double)n;
ie., (a+b+c)/n = a/n + b/n + c/n