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this will not work. return type is included when comparing the signature. (at least with C++ it is

it will return string

I think BabelFish was right. The following code won't compile in VS 2008.

class Base
{
public:
Base() {};
virtual ~Base() {};

virtual int foo() { cout << "base foo" << '\n'; };
};

class Derived : public Base
{
public:
Derived() {};
~Derived() {};

void foo() { cout << "derived foo" << '\n'; };
};

You cannot change the return type of virtual function. its an error

Method overriding in wikipedia

in C++, if class B is a subtype of class A, then all member functions of B must return the same or narrower set of types as A

and string is wider than int...

Confliciting return type error is thrown by compiler in such situation. nothing like more or less restrictions/

you are not allowed to change the return type of the virtual function.You can change argument list though.

new types may not be defined in a return type

will get compilation error.
error: conflicting return type specified for ‘virtual void Derived::foo()’

overriding doesn't depend upon return type means ,you will return only base or derived class object or ref or pointer

overriding doesn't depend upon return type means ,you will return only base or derived class object or ref or pointer

overriding does not depend on return type. it depends on function name and signature.
so it wont be compiler error.

Napolean is right. Should not have any compiler error. If you want access function in base class from derived instance, you can do

int i = b->Base::function();