Adobe Interview Question for Software Engineer / Developers






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1
of 1 vote

Local version of the function is called

- Anonymous June 14, 2010 | Flag Reply
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0
of 0 vote

core dump.

- Anonymous May 30, 2010 | Flag Reply
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0
of 0 vote

Virtual table is not created when constructor is called.. calls local version of the function

- Karthik Raj June 21, 2010 | Flag Reply
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0
of 0 votes

It does not really matter when the virtual table is created. Depending upon the version of the compiler, it could optimize the creation of the virtual table for a class before or after the constructor is called. It does not make sense to wait until the compiler sets up the object. Because then it is too late. Checkout the book on the C++ object model by Lippman

- Manish June 25, 2010 | Flag
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0
of 0 vote

When Object is instantiated constructors are executed from top to bottom (Base to derived) in such case if base class constructor call virtual function it calls the base class version of that function only because base class constructor never knows that we are part of the bigger derived class. so the only implementation he can find is his own.

- Saumitra Bhave August 01, 2010 | Flag Reply
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0
of 0 vote

class Base
{
    public:
    Base()
   {
      Fun();
   }
   virtual void Fun( )
   {
     cout<<"\n I am in virtual function\n";
   }
};
class Derived:public Base
{
   public:
   void Fun()
   {
     cout<<"\n I am in the Derived class";
     Base::Fun( );
   }
};

void main()
{
  Derived d;
  Base *b = &d;
}

- Saumitra Bhave August 01, 2010 | Flag Reply
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0
of 0 votes

`main' must return `int'

- Anonymous September 11, 2010 | Flag
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0
of 0 vote

Code generated for Constructor of a class by compiler resolved all the function statically including virtual function called within constructor.

- Amit June 18, 2014 | Flag Reply


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