CareerCup

Great solution Anant !

solution seems incomplete.. boundary cases shud be considered.. like (11:50 AM, 15) will make it 12:05 PM and vice versa for PM case..

I would add the case at the end to check
if (Suffix==AM && Hrs>12) --> Hrs=Hrs-12 and Suffix = PM

Similar case for PM.

solution seems incomplete.. boundary cases shud be considered.. like (11:50 AM, 15) will make it 12:05 PM and vice versa for PM case..

I would add the case at the end to check
if (Suffix==AM && Hrs>12) --> Hrs=Hrs-12 and Suffix = PM

Similar case for PM.

how about this?

let from first argument we get hh, mm and meridian = {AM = 0, PM = 1}. from second argument we get x the minutes to be added.
1. mm = (mm+x)%60;
2. hh = ((mm+x)/60+hh)%24
3. if (hh > 12) { meridian = 1-meridian; hh %= 12;}

how about this?

let from first argument we get hh, mm and meridian = {AM = 0, PM = 1}. from second argument we get x the minutes to be added.
1. mm = (mm+x)%60;
2. hh = ((mm+x)/60+hh)%24
3. if (hh > 12) { meridian = 1-meridian; hh %= 12;}

anant's method with a small change..
convert "HH" to minutes by HH*60
now add MM to HH*60,
add the x minutes to be added.
If AM leave it as HH*60 + MM +x else make the HH*60+MM+x+ (12*60)

converting back to the format needed should be trivial right?

mm = (mm+x)%60;
if (suffix == PM)
hh = hh + 12;
hh = ((mm+x)/60+hh)%24
if (hh > 12) { hh %= 12; Suffix = PM}
else {Suffix = AM}

mm = (mm+x)%60;
if (suffix == PM)
hh = hh + 12;
hh = ((mm+x)/60+hh)%24
if (hh > 12) { hh %= 12; Suffix = PM}
else {Suffix = AM}

mm = (mm+x)%60;
if (suffix == PM)
hh = hh + 12;
hh = ((mm+x)/60+hh)%24
if (hh > 12) { hh %= 12; Suffix = PM}
else {Suffix = AM}

1.convert first argument in minutes 10*60 + 23
2. add iind to the minutes = 623 + 13
3. Minute = 636%60
4. Hrs = (int ) 636 / 60
5. return back the result like "hh:mm"