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Amazon Interview Question for Software Engineer / Developers






Comment hidden because of low score. Click to expand.
0
of 0 vote

Quick and dirty ...
- No check for overflow

int my_atoi(const char *s)
{
  
  int mval = 10;
  int val=0;

  for (val = 0; s && *s >= '0' && *s <= '9'; s++)
      val = val*mval + (*s - '0');
  return val;
}

- ismailbhai September 11, 2007 | Flag Reply
Comment hidden because of low score. Click to expand.
0
of 0 votes

To generalize it to any radix,

1. Change mval to radix (2,8,16 etc.)
2. The loop invariant should be changed to check for values between '0' and radix-1
2.a. Hex alphabets will need to be handled specially

- ismailbhai September 11, 2007 | Flag
Comment hidden because of low score. Click to expand.
0
of 0 vote

1)check for '-' sign
2)check for non integer characters
3)Handle the case for decimal numbers (e.g. 2.34)

- Anonymous January 03, 2008 | Flag Reply


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