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when i ran the above code with initial value 10, upper gets initialised but not lower.

I tried running the same .the lower doesn't get initialised. can somebody explain why?

I guess the names of the member variables appearing on the Initialization list should be in the same order as they appear in the class (declaration).

There initialization take place in order of there declaration,,,
so by that I mean first upper get initialized and after that lower,,
So in the previous questions assuming i to be 10
upper = unknow lower value + 1 //
lower = 10

from c++ primer: the initializer only shows which value to set which member, but the order of initializers has no meaning

compiler will set upper first, then lower

therfore
A1( int i ) : upper( lower+1 ) , lower( i ){ };
// lower = 10; upper = 11

Always remember the initialization order is
1) Super Class (Based on the inheritance order, not mem init list)
2) Memeber (Based on the order they declared in class, not mem init list)
3) Computation inside the constructor