CareerCup

What is wrong with this answer:

public static List<String> fizzbuzz(int start, int end, Map<Integer, String> lookups) {
		List<String> fizzBuzzList = new ArrayList();
		Set<Map.Entry<Integer, String>> entries = lookups.entrySet();
		  
		for (int i = start; i<=end;i++){				
			StringBuffer fbBuffer = new StringBuffer();		
			fbBuffer.append(i + " : ");
			for (Entry<Integer, String> entry : entries){		
				if ( i % entry.getKey() == 0){
					fbBuffer.append(entry.getValue());						
					}				
			}
			fizzBuzzList.add(fbBuffer.toString());
		}
			
		return fizzBuzzList;		
	}

Tested and works.

/*Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz".
	For numbers which are multiples of both three and five print "FizzBuzz".

	Additionally, instead of printing "Fizz" or "Buzz", create a lookup such that 3 --> "Fizz", 5 --> "Buzz", 7 --> "Woof" and so on. The signature of the method would be:

	List<String> fizzbuzz(int start, int end, Map<Integer, String> lookups) { ..}

	The expected output is of the format : 15:FizzBuzz, 21:FizzWoof, 105: FizzBuzzWoof, etc*/
	public static void fizzBuzzStuffs() {
		boolean is3 = false, is5 = false, is7 = false;
		String out = "";
		for (int i = 0; i < 100; i++) {
			is3 = isMultOf(i, 3);
			is5 = isMultOf(i, 5);
			is7 = isMultOf(i, 7);
			out = "";
			
			if (!is3 && !is5 && !is7) {
				System.out.println(i);
			} else {
				out = "";
				if (is3){out += "Fizz";	}
				if (is5){out += "Buzz";	}
				if (is7){out += "Wolf";	}
				System.out.println(out);
			}
		}
	}
	
	public static boolean isMultOf(int val, int mult) {
		return val%mult == 0;
	}

Thanks for the ans without using stringbuffer. It also covers tests using negative integers and 0.

Regarding whether the HashMap returns sorted order of keys, one cannot guarantee the order with HashMaps anyway, unless you use a LinkedHashMap. As long as the required value is displayed, its acceptable I guess.

for(i=0;i<n;i++)
{
if(a[i]%(15)==0)
  cout<<"FIZZBUZZ"<<endl;
else if(a[i]%3==0)
  cout<<"FIZZ"<<endl;
else if(a[i]%5==0)
  cout<<"BUZZ"<<endl;
}

public class Print1to10 {
public static void main(String[] args) {
int count = 1;
while (count < 100) {
{
{
if(count % 3 == 0)
System.out.print("FIZZBUZZ");

else

if(count % 5 == 0)
System.out.print("FIZZ");


}
}
System.out.print(count + " ");
count++;
}
}
}

good ans