Bloomberg LP Interview Question for Python Developers


Country: United States




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Straightforward level order traversal using a queue. Solution in Python below.

from collections import deque
class Node:
    def __init__(self, val):
        self.val = val
        self.left = None
        self.right = None

def level_order(root):
    q = deque([root])
    while q:
        currLevel = []
        qSize = len(q)
        for _ in range(qSize):
            curr = q.popleft()
            currLevel.append(curr.val)
            if curr.left: q.append(curr.left)
            if curr.right: q.append(curr.right)
        print(currLevel)

'''
Construct the following tree
        1
      /   \
     2    3
     /
    4
    /
    5
'''

one_node = Node(1)
two_node = Node(2)
three_node = Node(3)
four_node = Node(4)
five_node = Node(5)

one_node.left = two_node
one_node.right = three_node
two_node.left = four_node
four_node.left = five_node

level_order(one_node)

Output:

[1]
[2, 3]
[4]
[5]

- prudent_programmer June 17, 2019 | Flag Reply


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