Yahoo Interview Question

Country: United States

Comment hidden because of low score. Click to expand.
of 1 vote

Do you really have to write the code for this?

It appears like a math problem to me.

Assuming, the current point is p, q, r, s (left, right, bottom and top) from the edges. The farthest the point can go is the bounding rectangle of width 2k and height 2k and current point will be at the center.

So, just create that bounding rectangle and see how many points are outside that array and how many are inside. This gives you the probability.

Correct me, if I am wrong.

- Bala January 07, 2015 | Flag Reply
Comment hidden because of low score. Click to expand.
of 0 vote

We can revisit the same cell. So, mark it as visited

- Anonymous November 01, 2016 | Flag Reply

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