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binary: 0000 0101
1s complement: 1111 1010
add 1 to get 2s complement: 1111 1011

If we assume that the maximum word length is 8 bits,
The binary representation of -5 is 1000 0101
Then, 1's complement is 0111 1010
2's complement is 0111 1011

beginning with the signed 8-bit binary representation of the decimal value 5, using subscripts to indicate the base of a representation needed to interpret its value:

000001012 = 510

The most significant bit is 0, so the pattern represents a non-negative (positive) value. To convert to −5 in two's-complement notation, the bits are inverted; 0 becomes 1, and 1 becomes 0:

11111010

At this point, the numeral is the ones' complement of the decimal value 5. To obtain the two's complement, 1 is added to the result, giving:

111110112 = − 510

The result is a signed binary number representing the decimal value −5 in two's-complement form. The most significant bit is 1, so the value represented is negative.

beginning with the signed 8-bit binary representation of the decimal value 5, using subscripts to indicate the base of a representation needed to interpret its value:

00000101 = 5

The most significant bit is 0, so the pattern represents a non-negative (positive) value. To convert to −5 in two's-complement notation, the bits are inverted; 0 becomes 1, and 1 becomes 0:

11111010

At this point, the numeral is the ones' complement of the decimal value 5. To obtain the two's complement, 1 is added to the result, giving:

11111011 = − 5

The result is a signed binary number representing the decimal value −5 in two's-complement form. The most significant bit is 1, so the value represented is negative.

is -5 not stored as 2``s complement of 5 in memory??

2's compliment 0f -5 if 5.
for 8 bit it ll be 00000101.

As we know -5 is represented as 11111011

so 2's compliment is 1's compliment+1
1's compliment is 00000100+00000001 = 00000101 = 5 (decimal)

00001010

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don't you know we r of ur

111001.100

0101 is 5
then 1010 1's
then 1011 is two's

Why da why

Tq

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2's complement for -24

-3

_45