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let we already n bits have gone and currently we have n+ 1 th bit.
- ptr.earnmoney March 26, 2012for n bit we know the flag then calculate the flag for n+1 th bit as:
—-----------------------------------
n+1 th bit. last flag. new flag
0. 0. 0
0. 1. 2
0. 2. 1
1. 0. 1
1. 1. 0
1. 2. 2
proof: let last number with n bits: (3k+flag)
so next number will be 2(3k+last flag)+(n+1th) bit.
whenever flag is zero it will be divisible by 3.