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using stack u can do it easily !!
- Mike Max May 27, 2013Here is the algo :
Step-1: For the current node check whether it has a left child which is not there in the visited list. If it has then go to step-2 or else step-3.
Step-2: Put that left child in the list of visited nodes and make it your current node in consideration. Go to step-6.
Step-3: For the current node check whether it has a right child. If it has then go to step-4 else go to step-5
Step-4: Make that right child as your current node in consideration. Go to step-6.
Step-5: Check for the threaded node and if its there make it your current node.
Step-6: Go to step-1 if all the nodes are not over otherwise quit