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It doesn't work for types though.
- Sie March 26, 2013For example a function that takes an array of int and the array len:
myFunc(data, mysizeof(data) / mysizeof(int));
You should also add '(' and ')' around the expanded macro because of the '-' in the middle, to allow for its use in calculations like:
size_t foo = mysizeof(var1) / mysizeof(var2);
So:
#define mysizeof(data) ((char *)(&data+1)-(char *)(&data))