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Explaining the question further:-
- biraja1985 December 16, 2013Arr-3 is formed by eliminating 3rd, 6th, 9th ... (x*3)th from Arr-2
Now since Arr-2 was {1,3,5,7,9,11,13 ...} (after eliminating 2nd,4th,6th (x*2)th elements from Arr-1) -
Arr-3 eliminates 5(3rd element), 11(6th element) ... from Arr-2 and forms Arr-3={1,3,7,9,13,15 ...}
So Arr-k formed by removing x*kth element from Arr-(k-1) immediate preceding array of Arr-k.
Please revert if am still not clear.