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low = (6*n)-1;
high = (6*n)+1;
if((a-low) == 0)
if((a-high) == 0)
low = (6*n)-1;
high = (6*n)+1;
int i = 8;
a = a+(i&1);
What if you use 2 pointers and make one pointer ahead of another.
-if they are diff., then increment both pointers
-if they are the same, move pointer 2 (the one ahead) and find a value opposite to the pointer 1, then swap with pointer1++. Then put pointer1+=1 and bring back pointer 2 to pointer1++.
-do this until pointer2 has not reached end of list.
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XOR with 1's- goku December 03, 2007