CareerCup

4 bytes for the pointer, 0 for static, static var is stored in static memory.

so 4 bytes total

though the previous answer is correct, a catch is, it will be 8 bytes on 64bit machines

static variables are stored in the data segment or BSS of the process memory.

4

Is the size of the class and object always same ?Why is it so ?
If the class has static members, then these members are not stored in the object. Inspite of that will the class and object have the same size ?

What do you mean y size of a class..? Unless and until you instantiate, the memory will not be allocated right? Just class does not make sense right? Please clarify.

Yes, you are right. But, assuming that the object has been instantiated, the size of the class will be 8 bytes 'on paper' and 4 bytes for the object

It should be the same = size of obj and class.. run it on a computer
also depends on 32 or 64 bit..because a pointer size is 4 byte on 32 bits only.

'Size of class' doesn't make sense because it's an abstract notion. If you want to calculate all the memory that relates to it you should also take the size of the code (hint: some member functions are generated by the compiler automatically... and then optimized). The total size of that memory is really implementation dependent (i.e. on the compiler).

Size of the object of that type (class A) depends on:
1. the platform (at least sizeof(void*))
2. the compiler (consider alignment settings). Though sizeof(A) is unlikely to be different from sizeof(void*).
For the sake of experiment, try sizeof(B) on your machine:
class B{
int i;
double d;
}

Size of object should also take memory of this pointer (4 bytes)

tried on my 64bit windows, using VS2008, both of the sizes are 4 bytes...

There is no such a thing as 'size of the class'.
Size can be of a data or of instructions.
In this case no instructions, only data which is stored in different places.
So size of object of a class will be equal to size of a pointer.
The static var will be stored in separate place.