CareerCup

import re
arr = "hello world AAAAAABBBBBBBCCCCCChello"
sub = ['el', 'AA', 'BBB', 'BC']
for i in sub:
    arr = re.sub(i, '<b>' + i + '</b>', arr)
print arr

- rasmiranjanbabu March 27, 2018 | Flag Reply

And to me here the max repeating number is "2", so output should be "2"

- rasmiranjanbabu April 12, 2017 | Flag Reply

How come "5" is in the output? It is not repeated....
And why output is not sorted or First come first serve (like this "1 2 0 4 3")

- rasmiranjanbabu April 12, 2017 | Flag Reply

arr1 = [0,1,2,3, 4,5,6,7]
arr2 = [-1, 0,1,2,3]
arr = []
def mysort(arr1, arr2):
    i = 0
    j = 0
    while i < len(arr1) or j < len(arr2):
        if i < len(arr1) and j < len(arr2):
            if arr1[i] < arr2[j]:
                arr.append(arr1[i])
                i += 1
            elif arr2[i] < arr1[j]:
                arr.append(arr2[j])
                j += 1
            elif arr1[i] == arr2[j]:
                arr.append(arr1[i])
                arr.append(arr2[j])
                i += 1
                j += 1
        elif i < len(arr1):
            arr.append(arr1[i])
            i += 1
        elif j < len(arr2):
            arr.append(arr2[j])
            j += 1

    return arr

print(mysort(arr1, arr2))

- rasmiranjanbabu July 12, 2016 | Flag Reply

If at all I understood the question correctly, then here is my answer is in Python language

def camelcase(string, substring):
    flag = False
    arr = []
    if substring[-1].islower() or substring[0].islower():
        return []
    #return [i for i in string for j in substring if j in i]
    for i in string:
        for j in substring:
            if j not in i:
                flag = True
                break
        if flag == False:
            arr.append(i)
        flag = False
    return arr

print camelcase(['HelloMars', 'HelloWorld', 'HelloWorldMars', 'HiHo'], 'HeWorM')

- rasmiranjanbabu July 08, 2016 | Flag Reply

Can somebody make me understand if {{{HeWorM -> [HelloWorldMars] #contains caps and small letter}}} then why, {{{Ho -> [] # is not returning [HiHo]?????}}} What would happen if we are looking for {{{{{{HeWorMa -> [HelloWorldMars] # or [] empty list? }}} Anyways, if at all I have understood the question correctly, then here is my answer in Python {{{ def camelcase(string, substring): flag = False arr = [] if substring[-1].islower() or substring[0].islower(): return [] #return [i for i in string for j in substring if j in i] for i in string: for j in substring: if j not in i: flag = True break if flag == False: arr.append(i) flag = False return arr print camelcase(['HelloMars', 'HelloWorld', 'HelloWorldMars', 'HiHo'], 'HeWorM') }}} - rasmiranjanbabu July 08, 2016 | Flag Reply

def main():
    l = ["a1", "a2", "a3", "a4", "a5", "b1", "b2", "b3", "b4", "b5"]
    # [a1 a2 a3 a4 a5] [b1 b2 b3 b4 b5]

    l1 = []
    l2 = []
    j = t = len(l)//2
    i = 0
    while i != t:
        l1.append(l[i])
        l2.append(l[j])
        j += 1
        i += 1
    print(l1, l2)
    l = []
    for i , j in zip(l1, l2):
        l.append(i)
        l.append(j)

    print(l)

main()

- rasmiranjanbabu June 07, 2016 | Flag Reply

def main():
    l = ["a1", "a2", "a3", "a4", "a5", "b1", "b2", "b3", "b4", "b5"]
    # [a1 a2 a3 a4 a5] [b1 b2 b3 b4 b5]
    l1 = []
    l2 = []
    j = t = len(l)//2
    i = 0
    while i != t:
        l1.append(l[i])
        l2.append(l[j])
        j += 1
        i += 1
    print(l1, l2)
    l = []
    for i in range(len(l1)):
        l.append(l1[i])
        l.append(l2[i])

    print(l)

main()

- rasmiranjanbabu June 07, 2016 | Flag Reply

I came up with is solution

def main():
    l = ["a1", "a2", "a3", "a4", "a5", "b1", "b2", "b3", "b4", "b5"]
    # # [a1 a2 a3 a4 a5] [b1 b2 b3 b4 b5]

    l1 = []
    l2 = []
    j = t = len(l)//2
    i = 0
    while i != t:
        l1.append(l[i])
        l2.append(l[j])
        j += 1
        i += 1
    print(l1, l2)
    l = []
    for i in range(len(l1)):
        l.append(l1[i])
        l.append(l2[i])
 
    print(l)

main()

- rasmiranjanbabu June 07, 2016 | Flag Reply

def checkMatrix(w, h, Matrix):
    flag = True
    count = tmpcnt = 0
    #print(Matrix)
    while flag:
        for i in range(0, w):
            for j in  range(0, h):
                if (i == 0 or j == 0) or (i == w - 1 or j == h - 1):
                    pass#print(".")
                else:
                    endtoend = min(Matrix[i][0], Matrix[i][h-1])
                    #print(endtoend, Matrix[i][0], Matrix[i][h-1])
                    uptodown = min(Matrix[i-1][j], Matrix[i+1][j])
                    leftright = min(Matrix[i][j-1], Matrix[i][j+1])
                    newList = [Matrix[i-1][j], Matrix[i][j-1], Matrix[i+1][j], Matrix[i][j+1]]

                    minval = min(newList)
                    if minval > Matrix[i][j]:#Matrix[i][j] < endtoend and Matrix[i][j] < uptodown:# and
                        Matrix[i][j] += 1
                        count += 1
                    elif endtoend > Matrix[i][j]:
                            #if i-1 != 0 and j-1 != 0 and i+1 != w - 1 and j-1 != h - 1:
                            if w < h:
                                if endtoend == Matrix[i][j] + 1:
                                    Matrix[i][j] += 1
                                    count += 1
                            else:
                                if Matrix[i-1][j] > Matrix[i][j]:
                                    Matrix[i][j] += 1
                                    count += 1

                        # if h > w and uptodown > Matrix[i][j]:
                        #     Matrix[i][j] += 1
                        #     count += 1
                        #
                        # else:#if w >= h and uptodown > Matrix[i][j]:
                        #     Matrix[i][j] += 1
                        #     count += 1
                if tmpcnt == count and i == w - 1 and j == h - 1:
                    flag = False
        tmpcnt = count
    #print("\n", count, Matrix)
    return count

def GetWaterLevel(input1,input2,input3):
    global flag
    w, h = input1, input2
    count = 0
    newList = []
    Matrix = [input3[i:i+h] for i in range(0, len(input3), h)]
    return checkMatrix(w, h, Matrix)


GetWaterLevel(4, 6, [3, 3, 4, 4, 6, 2,   3, 1, 3, 6, 1, 6,   7, 3, 1, 6, 6, 1])
GetWaterLevel(6, 3, [3, 3, 7, 3, 1, 3, 4, 3, 1, 4, 2, 6, 4, 1, 4, 2, 4, 1])

- rasmiranjanbabu April 27, 2016 | Flag Reply

Here is my code goes in Python

# input1 n = no. of employees 4
# input2 array of n elements  {2, 1, 1, 0}
# Output [4, 2, 1, 3]
# 0 [2, 1, 1, 0] [4, 2, 1, 3]
# 1 [2, 1, 1, 0] [4, 2, 1, 3]
# 2 [2, 1, 1, 0] [4, 2, 1, 3]
# 3 [2, 1, 1, 0] [4, 2, 1, 3]

import copy


def findLogic(temp, input2):
    for i, (k, v) in enumerate(zip(temp, input2)):
        count = 0
        if i == 0:
            countList = []
        j = i + 1
        #print(i, temp, input2)
        if j in input2:
            #print(i, temp, input2, input2.index(j))
            for l in range(input2.index(j), -1, -1):
                if l >= 0 and j <= (len(input2)-1):
                    if j < input2[l]:
                        count += 1
            countList.append(count)
            if countList == temp:
                #print(input2)
                print("{", end="")
                for i in input2:
                    print(i, end="")
                    if input2.index(i) != len(input2) - 1:
                        print(",", end="")
                print("}", end="")
                return 1

def PlaceNumbs(input2, l, r, temp):
    if l == r:
        if findLogic(temp, input2):
            return
    for i in range(l, r):
        input2[l], input2[i] = input2[i], input2[l]
        PlaceNumbs(input2, l + 1, r, temp)
        input2[l], input2[i] = input2[i], input2[l]

#def FinalOrder(n, input2):
def uniqueValue(input1,input2):
    n = input1
    temp = copy.deepcopy(input2)
    input3 = []
    for i in range(1, n+1):
        input3.append(int(i))
    PlaceNumbs(input3, 0, n, temp)

uniqueValue(4, [2, 1, 1, 0])
print("\n")
uniqueValue(8, [1, 2, 1, 1, 1, 1, 0, 0])

- rasmiranjanbabu April 25, 2016 | Flag Reply

unable to understand the question. Can anybody tell the meaning of line

you are given a int[], the ith element of which represents the number of taller employees to the left of the employee with height i (where i is a 1-based index)

- rasmiranjanbabu April 22, 2016 | Flag Reply

youtube com/watch?v=PqbcO-PijCc

- rasmiranjanbabu February 16, 2016 | Flag Reply

Take A simple shape example

class Shape {
virtual  void draw();
}
class rect:public shape{
void draw();
}

// Now if I want to add/register another class as circle then I can do like
class circle:public shape{
void draw();
}

I hope, I answered your question. If anyone has better answer please answer it.

- rasmiranjanbabu June 09, 2015 | Flag Reply

As far as my knowledge the default value of global variable is garbage.
I think u r right. Bt in this context I have one question that,
Uninitalized global variable stored in bss segment and the initialized global variables stored in data segment. Then if the compiler autmatically sets the value of global variable to Zero. Then what is the requiremnt of bss segment. And what is the use of "static" keyword, as it also does the same, if both have declared in the same file. Look at the below example;

int i;//Compiler sets the value to Zero.
int j = 0;// Here user sets to Zero.
static int k;//Default is Zero
main()
{
printf("%d...%d...%d",i, j, k);
}

What makes the difference in the above program?

- rasmiranjanbabu August 15, 2013 | Flag Reply

Naveen, Thanks for the answer, but if "int" is of 4 bytes then how can we allocate?

- rasmiranjanbabu August 11, 2013 | Flag Reply

I hope this link may help you
tianrunhe . wordpress . com/2012/06/10/transform-one-word-into-another-by-changing-only-one-letter-at-a-time/
remove the spaces and add http

- rasmiranjanbabu May 24, 2013 | Flag Reply

@Sarvan, I think your answer is really good. But just want some psuedo code.
Could you pls write some pseudo code?

- rasmiranjanbabu May 17, 2013 | Flag Reply

http : // stackoverflow . com/questions/2362097/why-is-the-size-of-an-empty-class-in-c-not-zero

- rasmiranjanbabu March 03, 2013 | Flag Reply

Finally See the answer

int main()
{
	char *abc = "01011011001";
	vector<char> def;
	int zero = 0;
	while(*abc != NULL)
	{
		if(*abc == '0')
		{def.push_back(48);
			abc++;}
		else
		{abc++;zero++;}
	}
	while(zero!=0)
	{def.push_back(49);zero--;}
	for (unsigned n=0; n<def.size(); ++n) {
		cout << def.at( n ) ;//<< " ";
		//printf("%c", def.at( n ));
    }
	cout <<"\n";
	system("pause");
	return 0;
}

- rasmiranjanbabu November 30, 2012 | Flag Reply

Adding to @redbanana.blueapple answer,
You can use below code for more better understnding.

/**
    I am a boy -> boy a am I

    */
    #include<stdio.h>
    #include<stdlib.h>
    #include<string.h>
    int main()
{
    int i, j, n, temp, temp_i, cnt;
    //char *array = "Samsung";
    char array[1000];
    char newarr[strlen(array)];
    printf("Enter The String: \n");
    gets(array);

    for(i = (strlen(array)-1), n = 0, j = 0; i >= 0; i--)
    {
     if( array[i] != ' ')
     {
         n++;
     }
     else
     {
         temp = n;
         temp_i = i;
         for(n = 0; n <= temp; n++)
         {
           //  i = i + 1;
             newarr[j++] = array[i++];
         }
         i = temp_i;
         n = 0;
     }

if(i == 0)
{
newarr[j++] = ' ';
temp = n;
temp_i = i;
for(n = 0; n <= temp; n++)
{
// i = i + 1;
newarr[j++] = array[i++];
}
i = temp_i;
n = 0;
}


//newarr[j++] = array[i];
}
newarr[j] = '\0';
cnt = 0;
for(j = 0; j <= (strlen(newarr)-1); j++)/*This is not required just do some R n D*/
{
newarr[j] = newarr[++cnt];
}
// printf("The first element is %c \n", newarr[1]);
puts(newarr);
return 0;
}

- rasmiranjanbabu November 30, 2012 | Flag Reply

But when i replaced long int y[5] to char i[5]; and int x[5] to char x[5].
Then also the result is 15 and 15. So could you please tell me why?
To my knowledge it should print element stord in 1st bit //x[0], y[0].
Don't you think so?

- rasmiranjanbabu September 19, 2012 | Flag Reply

#include <stdlib.h>
#include <math.h>
#include <string.h>
int main()
{
int i, j;
char *mac_add = "ab:cd:ef:12:34:56";
char result[strlen(mac_add)];
j = 0;
for(i = 0; i <= strlen(mac_add); i++)
{
if(mac_add[i] != ':')
{
result[j++] = mac_add[i];
}
else
{
result[j++] = ',';
result[j++] = ' ';// Not required
// j++;
}
}
puts(result);
return 0;
}

- rasmiranjanbabu March 30, 2012 | Flag Reply

According to question all values should be in ascending order and push the zero to the end...
Find the answer below


#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
// printf("Hello world!\n");
int i, j, x;
int arr[7] = {1, 2, 0, 4, 0, 0, 8};
int arr1[7];
for(i = 0; i < 7; i++)
{
for(j = (i + 1); j < 7; j++)
{
if(arr[i] > arr[j])
{
x = arr[i];
arr[i] = arr[j];
arr[j] = x;
}
else
{

}
}

}

for(i = 0; i < 7; i++)
{
printf("The arr[%d] = %d \n", i, arr[i] ); // 0 0 0 1 2 4 8
}
for(i = 0, j = 0; i < 7 ; i++)
{
if(arr[i] != 0)
{
arr1[j] = (arr[i]); //<< i)/pow(2, i);
j++;
}

}
for(i = j; i < 7; i++, j++)
{
arr1[j] = 0;
}
for(i = 0; i < 7; i++)
{
printf("The arr1[%d] = %d \n", i, arr1[i] ); //1 2 4 8 0 0 0
}

return 0;
}

- rasmiranjanbabu March 27, 2012 | Flag Reply